Recent content by original1
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A Proton is orbiting a metal ball
That makes perfect sense... thanks for all your help!- original1
- Post #25
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
F_cp = F_c so F_cp=(kq_1q_2)/r^2 q_1 = 1.602*10^-19 C q_2= (F_cp*r^2)/(k*q_1) q_2= [(2.02*10^-16 N)(0.0069 m)^2]/[(8.99*10^9 Nm^2/C^2*1.602*10^-19 C)] q_2= 6.68*10^-12 C this looks right, thank you! do you know why the answer has to be negative value?- original1
- Post #23
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
the final answer should come to about -#*10^-12, but this is nowhere near that :(- original1
- Post #20
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
You're right, I corrected it and it comes to 0.0069 m. Do you know if this procedure I used is correct??- original1
- Post #19
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
new calculation: r = r = 1/2(1 cm) + 1.9 mm = 0.0069 m m_proton = 1.67*10^-27 kg T = 1.5 us = 1.5*10^-6 s v_cp = omega*r = (2pi*r)/T = [2pi(0.0069 m]/(1.5*10^-6) = 2.89*10^4 m/s F_cp = (mv^2)/r = (1.67*10^-27 kg*(2.89*10^4 m/s)^2)/0.0069 m = 2.02*10^-16 N F_cp = F_c so...- original1
- Post #17
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
no wait, r = 1/2(1 cm) + 1.9 mm = 0.0069 m- original1
- Post #16
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
radius would be r = 1/2(0.019 m) = 0.0095 m- original1
- Post #15
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
I just saw your reply as I entered this post above, what am I doing wrong?- original1
- Post #14
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
r = 1.0cm + 1.9 mm = 1.19 cm = 0.0119 m m_proton = 1.67*10^-27 kg T = 1.5 us = 1.5*10^-6 s v_cp = omega*r = (2pi*r)/T = [2pi(0.0119 m]/(1.5*10^-6) = 4.98*10^4 m/s F_cp = (mv^2)/r = (1.67*10^-27 kg*(4.98*10^4 m/s)^2)/0.0119 m = 3.49*10^-16 N F_cp = F_c so F_cp=(kq_1q_2)/r^2...- original1
- Post #13
- Forum: Introductory Physics Homework Help
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A Proton is orbiting a metal ball
so F_cp=(mv^2)/r and F_cp=F_c so F_cp=(kq_1q_2)/r^2 also q_1=q_2 --> F_cp=(kq^2)/r^2 Is this right?- original1
- Post #11
- Forum: Introductory Physics Homework Help