Recent content by Ottoturbo

The mass of the wheel is only about 0,1 kg. It's loaded on it's axle with 20kg.

Could I say as the wheel starts to rotate around the edge that the force from the edge must be the same as the centripetal force, F = mv²/r. The wheel has neglectable mass and stops rotating. F=20*1,5²/0,06=750N

So conservation of energy will be: \frac{1}{2}mv_{1}^{2}=\frac{1}{2}mv_{2}^{2}-mgh \frac{1}{2}\cdot20\cdot1.5^{2}=\frac{1}{2}\cdot20\cdot v_{2}^{2}-20\cdot9.81\cdot0.03v_{2}=1.68 m/s This gives a higher end speed, top of the egde than to start with, 1.5m/s. The mass is rotating around the...

Homework Statement Wheel is hitting edge at a x-component speed of 1.5m/s, what is the force it is subjected to when going over the edge. The wheel is loaded with 200N Btw, the line with an 60 degree angle to to x-axis/ground is the tangent not a ramp. Homework Equations acceleration...