Recent content by PandaBoy

2. Yes you are on the right track. You already found your k, its only proving the other part of the equation left. You might need some basic trigonometric identities to finish your proving.

Hey I got my answer! Thanks for the help Doc! I understood some part wrongly but I fixed my understanding now. I think I should have no problem with the other questions now. Appreciate your real direct-to-the-point replies. Have a good day sir!

Oh so I would use the change in velocity to find the acceleration and thus make it into my resultant force? Hmm which means : Uy = 2sin15° = 0.52m/s Vy = 4sin35° = 2.29m/s Ux = 2cos15° = 1.93m.s Vx = 4cos35° = 3.28m/s In which I have t=35s Which means my a for x and y-component...

A 325-kg boat is sailing 15.0° north of east at a speed of 2.00 m/s. Thirty seconds later, it is sailing 35.0° north of east at a speed of 4.00 m/s. During this time, three forces act on the boat: a 31.0N force directed 15.0° north of east, a 23.0N force directed 15.0° south of west and F Find...