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Graduate Identity for exponential function with imaginary arguments
Thanks. I was making it way too complicated with trig identities and series and...- ParityCheck
- Post #3
- Forum: Calculus
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Graduate Identity for exponential function with imaginary arguments
I have seen the following identity used. Exp[iw/2]-Exp[iw/2]=Exp[iw]-1 I can't find this in any book and I can't prove it myself. The left side equals 2isin(w/2) The right side equals cos(w)+isin(w)-1 On the face of it, that seems to make the identity absurd How can one go about proving...- ParityCheck
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- Exponential Exponential function Function Identity Imaginary
- Replies: 2
- Forum: Calculus