Recent content by patelpalak

ok thanks all i got the answer... appriciate your help...thanx once again!:smile:

ok here's what i did d sin (theta) =m*lamdba therefore, d=m*lambda/ sin(theta) m=5, since its fifth fringe lambda= 546*10^-9 theta = 0.150 degrees so, d=(5)(546*10^-9)/sin(0.150) and i get 0.001042 meters but it gives me wrong answer...! thats all i did ...

Homework Statement The green line of gaseous mercury at 546nm fals on a double-slit apparatus. If the fifth dark fringe is at 0.150 degree from the centerline, what is the slit separaton? Homework Equations d sin (theta) = m* lambda The Attempt at a Solution ok i used the...

hey i got part b but have problem with part C is this right? B^2 = ave. S *2* 4*pie*10^-7/ (3*10^8) = T

ok i got 160 W/m^2 thanx for the help!

is there 4 in the bottoom becuz isn't the formula is ave s= p/4*pie*r^2 ?

Homework Statement A laser blackboard pointer delevers 0.10-mW average power in a beam 0.90 mm in diameter. Homework Equations a) Find the average intensity. b) Find the peak electric field. c) Find the peak magnetic field. The Attempt at a Solution ok for part a) i used...

Homework Statement In this problem, you will use Lenz's law to explore what happens when an electromagnet is activated a short distance from a wire loop. You will need to use the right-hand rule to find the direction of the induced current. Finally, the switch on the electromagnet is...