Recent content by Patrica87

Attempt at a Solution: I started by identifying the forces acting on the block. The component of gravity parallel to the incline is: Fgravity, parallel=(5)(9.8)sin⁡(30∘)=24.5 NF_{\text{gravity, parallel}} = (5)(9.8)\sin(30^\circ) = 24.5\text{ N}Fgravity, parallel=(5)(9.8)sin(30∘)=24.5 N The...