Recent content by Paul2011

Doesnt say that Q=-4q only, just to prove that Q=-4q and to verify the position.

Thanks a lot. Really appreciate it, definitely understand it now.

Ok, so if I find F_ab = -(4q^2)/9a^2 and -F_cb = (16/9)q^2/a^2. F_ba is the same as F_ab which is -(4q^2)/9a^2 and F_ca = 4q^2/a^2. Not quite sure if I should replace a^2 with the given position of x=3a or not

If I use the point charge formula F= (kq_1q_2)/r^2 then my r would be from origin to l so total distance of l. And I would have to add them up from the origin to x=l. I am sure I'm over complicating this problem. I definitely understand the concept but somethings not clicking.

Ok, after reading what you have had to say I am a little embarrassed to say that I am not grasping the whole thing. I under stand that the rod can be visualized as a bunch of discs which would run from the origin to x=l, which I wrote on my coordinate plane as (l,0). the end points are from...

Homework Statement A charge -q and a charge 4/9q are located at coordinates x = 0 and x = a, respectively. If you place a third charge so that all three are in static equilibrium, justify that its position and its charge,respectively, can only be x=3a Q=-4q Homework Equations...

Homework Statement A thin rod runs along the x-axis from the origin to x = l. Its linear charge density (C/m) is given by λ = λ_0(x/l)^2 sin (x/lπ), where λ_0 is a constant. Show that at the origin, E(0)=〖-λ〗_0/(2π²€_0l) Homework Equations The Attempt at a Solution Sorry I...

Ok, so this is what I've done based on your insight (thanks btw). (a+b)/2 = (-2q-4q)/2 = -3q a=-3q , b=-3q, c=8q a=-3q, b=0q, c=8q (c+b)/2 = (8q+0q)/2 = 4q a=-3q , b=4q, c=4q F_ac = (-3q)(4q)/4π€_o l^2 F_ac = 3q^2/π€_o l^2 F_bc = (4q)(4q)/4π€_o l^2 F_bc = 4q^2/π€_o l^2...

Homework Statement A) Three conducting spheres, a, B, and c, form an equilateral triangle of side length "l" and have initial charges of -2q, -4q, and 8q, respectively. Show that the magnitude of the electrostatic force between spheres  a and c is given by F_ac= (4q^2)/(π€_o l^2 )...