Recent content by paulmdrdo1

Hello. Do you guys know if there is an identity related to this expression $$\cos(A+B)\cos(A+C)$$ If so, can you help me how to derive it? I need it for the derivation of the formula from my circuits analysis course. Thanks.

Where is the complete solution to this problem? Anyone?

We have 4 pills in total. Splitting each pill into half we will have 4 half B pills and 4 half A pills. Since we don't know which is which, there is a posibility that you might take 3 half pills B and 1 half pill A or 3 half pills A and 1 half pill B or 4 half pills B or 4 half Pills A.

The doctor told you to take 2 different kind of pills (Pill A, Pill B) for ten days everyday. Both pills look exactly the same (same weight, color, shape, size, etc…;). If you take more than 1 pill of the same kind per day, you will die. Furthermore, if you do not take 1 Pill A, and 1 Pill B...

I'm still not sure how to continue from there. Do I need to use rational roots theorem? And What do you call that method? Does this always work on the polynomials that has the same form I posted?

What technique did you use to determine the pair of numbers to be used to rewrite the expression? Was it by trial and error?

Factor $30x^4-41x^3y-129x^2y^2+100xy^3+150y^4$. Please help me get started. I tried grouping the terms but still can't see any factorization that is familiar to me. Thanks.

I'm just curious as to how to go about factoring a polynomial like this one $6x^4+17x^3-24x^2-53x+30$ without using rational root theorem? Thanks

Can you explain the part of the solution where v2/v1 = a2/a1were being squared and cubed repectively? Thanks!

hello greg! Can you pin point what I did wrong in my attempt? what I did in my solution was, after putting 0 in the units digit, I counted the possible choices for tens digit first rather than hundreds digit. Thus giving me 6 choices for the tens place as I omit 0. And 5 choices for hundreds...

Arent we suppose to go from units to hundreds digit?

How many 3 digit even numbers can be formed from 0, 1, 2, 3, 4, 5 and 6 with no repetition? My attempt: $\frac{5}{H} \times \frac{6}{T} \frac{0}{U} = $ 30 numbers ending with zero not including two digit numbers starting with zero$\frac{4}{H} \times \frac{6}{T} \frac{2}{U} = $ 24 numbers...

A certain mechanical part of a machine can be defective because it has one or more out of three possible defects: insufficient tensile strength, a burr or a diameter outside of tolerance limits. In a lot of 500 pieces 19 have tensile strength defect, 17 have a burr, 11...

Hello! From what I understand when you know the roots of a certain polynomial we can use those roots to get the factored form a that polynomial. Is the expression $$\left(x+\frac{5}{6}\right)\left(x-\frac{27}{16}\right)$$ equivalent to $96x^2-82x-135$? And if it is how do we transform it to...

Hello! From what MarkFl provided, he used the quadratic formula to find the roots of $96x^2-82x-135$ Since the roots are x = -5/6 and x = 27/16 I am thinking that the factored form of $96x^2-82x-135$ Would be $(x+\frac{5}{6})(x-\frac{27}{16}) = (\frac{(6x+5)(16x-27)}{96})$ So the completely...