Recent content by pechan

Obviously this is a class 3 lever. The formula I found is Fe = Fl dl / de Fe being the required effort. Fl being the load.(tower weighs 8000 lbs) dl being the distance from the load to the point of effort (cylinder attachment point on tower) de being the distance from the fulcrum (tower...

These are the calculations I came up with. I think I am missing something as this seems like a large number at 150k lbs. Your Thoughts?

Would I need to split the tower into 70 weights for each foot and multiply these by their distance from the cylinder attachment point? ie. For the first 20 feet 2500/20 =125 lbs, so I run 20 calculations starting with 1 ft X 125 = 125 ... 20 ft X 125 lbs = 2500 lbs. Adding up all calculations...

Hello, I could use some help determining what size hydraulic cylinder I need to be able to tilt my turbine tower up. What I have is a 70 ft tower where the first 20 feet weigh 2500 lbs, the 2nd 20 weigh 1700 lbs and the 3rd 20 ft weigh 1000 lbs and the last 10 feet weigh 1000 lbs. For a total...