Recent content by pereus

At the top the projectile is moving with the velocity Vx which is equal to v0cos(theta). There is no velocity in the y direction

I know that the velocity at the top is Vx. That is how I was able to make 4vx = to 4v1/4

Homework Statement The speed of a projectile when it reaches its maximum height is 1/4 the speed when the projectile is at 1/4 its maximum height. What is the initial projection angle? Answer in units of ◦ Homework Equations v2 = v02 + 2a(delta s) 4Vx = v1/4 The Attempt at a Solution...