Recent content by perpetium

Defennder thanks for response I have already evaluated that integral in the y=f(x) form, through trigonometric substitution Now I need to evaluate it in parametric form...

I know this is very simple, but the end integral just kills me Homework Statement Given equation in Parametric form x=\sqrt{2t+1}), y=6t Find arc length Homework Equations The Attempt at a Solution take x' & y' then Take integral of \int\sqrt{1/(2t+1) + 36} This is where I got stuck ...is...