Defennder thanks for response
I have already evaluated that integral in the y=f(x) form, through trigonometric substitution
Now I need to evaluate it in parametric form...
I know this is very simple, but the end integral just kills me
Homework Statement
Given equation in Parametric form
x=\sqrt{2t+1}), y=6t
Find arc length
Homework Equations
The Attempt at a Solution
take x' & y'
then Take integral of \int\sqrt{1/(2t+1) + 36}
This is where I got stuck ...is...