1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Arc Length in Parametric equation

  1. Dec 2, 2008 #1
    I know this is very simple, but the end integral just kills me

    1. The problem statement, all variables and given/known data
    Given equation in Parametric form
    x=[tex]\sqrt{2t+1}[/tex]), y=6t
    Find arc length

    2. Relevant equations



    3. The attempt at a solution
    take x' & y'
    then Take integral of [tex]\int[/tex][tex]\sqrt{1/(2t+1) + 36}[/tex]

    This is where I got stuck ........is there a simple way to solve this integral ???
    Thank you
     
  2. jcsd
  3. Dec 2, 2008 #2

    Defennder

    User Avatar
    Homework Helper

    You didn't specify the limits of t for which the arc length is to be evaluated. You can try an alternatve approach here. Note that you can easily express the graph in the form y = f(x). Do that, and use the other formula to calculate arc length. Should be easier to integrate. Also remember to find the values of x for which the arc length is to be calculated.
     
  4. Dec 2, 2008 #3
    Defennder thanks for response
    I have already evaluated that integral in the y=f(x) form, through trigonometric substitution

    Now I need to evaluate it in parametric form.....
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?



Similar Discussions: Arc Length in Parametric equation
Loading...