# Arc Length in Parametric equation

1. Dec 2, 2008

### perpetium

I know this is very simple, but the end integral just kills me

1. The problem statement, all variables and given/known data
Given equation in Parametric form
x=$$\sqrt{2t+1}$$), y=6t
Find arc length

2. Relevant equations

3. The attempt at a solution
take x' & y'
then Take integral of $$\int$$$$\sqrt{1/(2t+1) + 36}$$

This is where I got stuck ........is there a simple way to solve this integral ???
Thank you

2. Dec 2, 2008

### Defennder

You didn't specify the limits of t for which the arc length is to be evaluated. You can try an alternatve approach here. Note that you can easily express the graph in the form y = f(x). Do that, and use the other formula to calculate arc length. Should be easier to integrate. Also remember to find the values of x for which the arc length is to be calculated.

3. Dec 2, 2008

### perpetium

Defennder thanks for response
I have already evaluated that integral in the y=f(x) form, through trigonometric substitution

Now I need to evaluate it in parametric form.....