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Arc Length in Parametric equation

  1. Dec 2, 2008 #1
    I know this is very simple, but the end integral just kills me

    1. The problem statement, all variables and given/known data
    Given equation in Parametric form
    x=[tex]\sqrt{2t+1}[/tex]), y=6t
    Find arc length

    2. Relevant equations

    3. The attempt at a solution
    take x' & y'
    then Take integral of [tex]\int[/tex][tex]\sqrt{1/(2t+1) + 36}[/tex]

    This is where I got stuck ........is there a simple way to solve this integral ???
    Thank you
  2. jcsd
  3. Dec 2, 2008 #2


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    Homework Helper

    You didn't specify the limits of t for which the arc length is to be evaluated. You can try an alternatve approach here. Note that you can easily express the graph in the form y = f(x). Do that, and use the other formula to calculate arc length. Should be easier to integrate. Also remember to find the values of x for which the arc length is to be calculated.
  4. Dec 2, 2008 #3
    Defennder thanks for response
    I have already evaluated that integral in the y=f(x) form, through trigonometric substitution

    Now I need to evaluate it in parametric form.....
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