Recent content by peter270357
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Solving Harder Trig Identity - Peter's Question
yessss, it does ... thanks for that :-)- peter270357
- Post #9
- Forum: Precalculus Mathematics Homework Help
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Solving Harder Trig Identity - Peter's Question
but tbh, Jedishrfu, I thought it was more like (s-c)* (1+ sc)- peter270357
- Post #7
- Forum: Precalculus Mathematics Homework Help
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Solving Harder Trig Identity - Peter's Question
Jedishrfu ... yes I got that ... and used the fraction top and bottom to get the RHS denominator right away .. but the top is proving to be a pig .. unless there's something dead easy I'm missing- peter270357
- Post #6
- Forum: Precalculus Mathematics Homework Help
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Solving Harder Trig Identity - Peter's Question
sorry sammy .. I meant top and bottom multiplied by that because it eliminates stuff and gives the denominator straight away but leaves the numerator slightly more complicated ... It's not homework guys , just a challenge .... and the theory is that we learn a bit plus a bit of experience...- peter270357
- Post #5
- Forum: Precalculus Mathematics Homework Help
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Solving Harder Trig Identity - Peter's Question
for the LHS i used a multiplier/simplifier of (sinx - cosx)/(sin^2 x) and re-arrangement to achieve the denominator of the RHS P- peter270357
- Post #2
- Forum: Precalculus Mathematics Homework Help
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Solving Harder Trig Identity - Peter's Question
[mentor note] moved to homework forum hence no template. HI, I'm just having a bit of trouble with the numerator part of this identity ... Resolving the the denominator is fairly straightforward but .. Can anyone shed light on the final couple of steps (sin^3 x - cos^3 x)/(sinx + cosx) =...- peter270357
- Thread
- Identity Trig
- Replies: 8
- Forum: Precalculus Mathematics Homework Help