PeterDonis's latest activity

It doesn't have to. The pilot wave is just a part of the Hamiltonian that determines B's equation of motion. It doesn't have to "know"...

It's worth nothing, though, that when you use the words "before" and "after", as I understand it, those are relativistically invariant...

"Photon" is a limited term. That's why I said "quantum EM field" instead when I referred to the treatment in Ballentine. Only a very...

More precisely, that the 4-momentum wave vector of the light was set at emission. In terms of wavelength, that determines the wavelength...

That's not quite true. In quantum optics, for example, it's quite common to treat photons in an essentially non-relativistic way. See...

For details about spin in Bohmian mechanics I recommend https://arxiv.org/abs/1305.1280 For a relativistic version of Bohmian mechanics...

You're missing the point. In BM, the "value" of spin is not something separate from the particle's position. When we measure "spin" in...

No, it doesn't. It just has to act on the B particle in such a way as to ensure that it comes out of the proper arm of whatever...

Yes it does; "pilot wave" is just another name for the wave function. What BM has that orthodox QM does not have is the unobservable...

As I understand it, the simple answer to the title question, when does the pilot wave action cease? is never. The pilot wave is always...

Please stop posting these kinds of statements. We all know what subforum we're in. What you do as a physician is irrelevant here...

You do realize that people post here for free on their own time, right? What you're asking for is something physicists in the relevant...

S-G Hamiltonian is proportional to Sz. [H,Sz]=0. Sz is conserved,I.e.,we get the same result in measurement performed in any future...

The OP question has been addressed. Thread closed.

Which means this... ...is exactly what we should expect since we have changed the observables. So I don't understand why you think this...