Recent content by PhilMTSU12

Does the final anwser look correct?

ok 2.8m= 1/2(9.8)t² 2(2.8)=2(1/2)(9.8)t² 5.6m= 9.8t² Divide 9.8 to both sides .5714=t² t=.756s d=Vot d=8(.756) d=6.048

i tried to quickly do all the work haha vert distance a= -9.8m/s Vo=0 V=? d=9.8m t=? using at+1/2at² 9.8= 1/2(9.8)t² 2(9.8)=9.8t² over 9.8=9.8 (the 9.8's cancel leaving) 2=t² t=square root of 2 t= 1.41 soo it will take 1.41s for the ball to hit the...

ok... The next problem is this A ball rolls off a table which is 2.8m high. If it leaves the table with a horizontal v of 8m/s, calc the distance from the base of the shelf at which the ball will strike the ground. I know i need to figure out how long it will take the ball to strike the...

so, I only needed to find the vertical distance? I did the horz distance for no reason... and why do i only need half of the equation?

ok vert= .24 and horz=1.76 what do I do with these 2 distances

ok Vertical a= -9.8m/s Vo=0 V=? d=9.8m t=.22 (9.8)(.22)+1/2(9.8)(.22²) d= 2.39

correction d= (8)(.22)+1/2(0)(.22²) d= (8)(.22) d= 1.76

Homework Statement A ball rolls off a table with a horizontal v of 8m/s. If it takes the ball .22s to hit the floor, how high was the shelf? Homework Equations d=Vot+1/2at² The Attempt at a Solution HORIZ a=0 Vo=8m/s V=8m/s d=? t=.22s d= (8)(.22)+1/2(8)(.22²) Is the...

the rate of change of velocity as a function of time. the rate is 6.3m/s², the distance the object travels or speed is what we are looking for and the time is 2 seconds. if the object has a constant accelerating of 6.3m/s² for 2 seconds I would think you could just multiply 6.3 times 2.

ahh, i had the wrong formula a = F/m what would be the net force and the mass?

Homework Statement Starting from rest, an object accelerates at a rate of 6.3 m/s² for 2 seconds. What is the speed of the object at the end of that time? Homework Equations V= d/t The Attempt at a Solution If I plug in the 2 seconds to the m/s² then i get 6.3m/4s=1.575...

divide 95 by 60 to get the answer in hours... 53.25miles/1.58hrs= 33.64mph

95min/53.25= 1.78mph... that seems to slow

Homework Statement A person travels at a constant speed of 66 miles per hour for 30 minutes, 27 miles per hour for 45 minutes, and stops for lunch for 20 minutes. Calculate the average speed for the entire trip (in miles per hour). Homework Equations N/A The Attempt at a Solution...