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    Parallel plate capacitor and magnetic field

    correction: using B= (uo id/2piR^2) r to find induced magnetic field inside a circular capacitor. uo=mu id=displacement current pi=3.14 R^2= radius of plate squared r= radius from center (point inside capacitor) I have values uo=1.256810^-6 (permeability constant) id= .280 R= 4...
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    Parallel plate capacitor and magnetic field

    Homework Statement A parallel plate air-filled capacitor is being charged as in figure. The circular plates have a radius of 4.0 cm, and at a particular instant the conduction current in the wires is .280 A. A. What is the displacement current density (jD) in the air space between the...
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