Recent content by phys01
-
P
Parallel plate capacitor and magnetic field
correction: using B= (uo id/2piR^2) r to find induced magnetic field inside a circular capacitor. uo=mu id=displacement current pi=3.14 R^2= radius of plate squared r= radius from center (point inside capacitor) I have values uo=1.256810^-6 (permeability constant) id= .280 R= 4...- phys01
- Post #5
- Forum: Introductory Physics Homework Help
-
P
Parallel plate capacitor and magnetic field
Homework Statement A parallel plate air-filled capacitor is being charged as in figure. The circular plates have a radius of 4.0 cm, and at a particular instant the conduction current in the wires is .280 A. A. What is the displacement current density (jD) in the air space between the...- phys01
- Thread
- Capacitor Field Magnetic Magnetic field Parallel Parallel plate Parallel plate capacitor Plate
- Replies: 4
- Forum: Introductory Physics Homework Help