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    How Do I Isolate Velocity in the Lorentz Factor Equation?

    My question is how do i solve for "v", that l should be an L lower case. as in lorentz factor "L". not a 1. sorry Like what should the final equation be?
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    How Do I Isolate Velocity in the Lorentz Factor Equation?

    What, you mean like this... \gamma(\sqrt{1-v^2/c^2})=1 then: finally finishing with; \sqrt{(1-1^2/\gamma^2)c^2}=v ??
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    How Do I Isolate Velocity in the Lorentz Factor Equation?

    Alright, I am not the best at algebra. So i was wondering if anyone could show me how to get the V out on its own in the lorentz factor equation l= 1/\sqrt{1-(v^2/c^2)} I tried to first times both sides by bottom then manipulate it but i just can't get it right. Any help would be...
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    An infinite ladder of resistors

    The network of resistors shown extends off to infinity. The resistors on the sides of the “ladder”, RS, are equal to each other,but different from the resistors in the center of the ladder,Rc .....Rs........Rs.....Rs a------^^^^^------c---------^^^^^------------^^^^^------------etc...
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