Recent content by physicisTboB

Yeah, that's it I guess you've been right that I didn't have to do that first ratio with the a and c. I never really saw it like that, thanks.

C does lie on the line, however it is not the total distance to the point.

No, c isn't the distance along the line, c is the hypotenuse of the triangle that is used to find the ratio of the x length to the distance along the line. Then using this ratio: deltax the total change in x c the hypotenuse of the triangle a the horizontal leg of the triangle z the distance...

So here's the equation with wil3's correction (with latex =D) c = \sqrt{((a)^2+(m*(x_o+a)+b-y_o)^2)} a, and c exist to establish legs of a triangle to get a ratio of line length to horizontal length, and yes I found this using the Pythagorean theorem. deltax is the horizontal distance from x_{o}...

So for a while i have been wondering if there was a way to find a point a certain distance along a linear function, so I decided that with my extreme pre-calc level of math that I would try and write an equation for it. long story short I would appreciate it if someone would take a look at the...

"Is it true that scientist have been able to accelerate photons at 99% the speed of light?" the photon will always travel at the speed of light in a vacuum this is the fundamental of Quantum physics, that time not the speed of light is the variable.