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    Displacement of a Rolling Ball with Initial Velocity and Constant Acceleration

    Well I know the displacement north is 30m, because i was given an acceleration and a time. From that I found the final velocity of 50m/s from the triangle these two velocities created. Using the motion formula V22 = V12 + 2ad , i found the displacement to be 90, not 260... And I have no idea how...
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    Displacement of a Rolling Ball with Initial Velocity and Constant Acceleration

    Homework Statement A ball rolling with an initial velocity of 40m/s[W] undergoes an acceleration of 5.0m/s2[N] for a period of 6.0 seconds. What is the displacement of the ball in the 6.0 seconds? The Attempt at a Solution Apparently the answer is 260m[W21°N] Please help!
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