Recent content by physicslady123

W=-qEd =-(1.6*10^-19)(23)(0.75) = -2.76*10^-18 J However, the answer is 2.76*10^-18 J. Why is the word done positive and not negative? Since it's traveling in the same direction as the electric field, shouldn't it be negative work?

Summary:: Confused on correction for contunuity I'm confused about one step for questions like this where you have to determine to accept or reject the null hypothesis. Sample size: 50 Number of successes: 23 Significance level: 10% Null hypothesis: p = 0.4 Accepted hypothesis: p > 0.4...

Question: In finance, the strong form of the efficient market hypothesis states that studying financial information about stocks is a waste of time since all public and private information that might affect the stock price is already reflected in the price of the stock. However, a study of 450...

e.g. 10.00cm = 0.0010 m, 16.38cm = 0.1638 m, 29.10 cm = 0.2910 m Or, would the sig figs for the meters be to 2 digits after the decimal (e.g. 16.38 cm = 0.16 m)

Yep. Word for word. My teacher posted the answer: 4.5*10^3m is the distance

I tried using the equation E(k)=1/2mv^2 and isolating for v but no mass was given. Then, I tried W=fd but there is no distance given. I don't know how to solve this.

F(net)=F(app)-F(resistance) ma=F(app)-F(resistance) (1.5*10^3)(16.67)=F(app)-600 25005=F(app)-600 P=ΔE/Δt P=25005/6 P=4167.5 W I got the incorrect answer (because I didn't take into account the resistance?). I am also confused about which Force value to use for the...

gravity.

I still wouldn't be able to calculate velocity for part b by using kinematics as I have 3 missing values (no acceleration, no final velocity, and no displacement). Would I have to assume that the velocity is constant?

a) E(mech)=E(k)+E(g) E(mech)=1/2mv^2+(0.2)(9.8)(0) E(mech)=19.6 J b) E(mech1)=E(mech2) E(k)+E(g)=E(k)+E(g) E(g)=E(k)+E(g) 0=1/2mv^2+(mgh) *No height is given so I can't solve using this method. It says instantaneous velocity meaning the velocity at...