Work Done on A Proton in an Electric Field

  • #1
physicslady123
10
0
Homework Statement:
Calculate the work done in moving a proton 0.75 m in the same direction as the electric field
with a strength of 23 N/C
Relevant Equations:
W=-qEd
W=-qEd
=-(1.6*10^-19)(23)(0.75)
= -2.76*10^-18 J

However, the answer is 2.76*10^-18 J. Why is the word done positive and not negative? Since it's traveling in the same direction as the electric field, shouldn't it be negative work?
 

Answers and Replies

  • #2
Gordianus
460
116
It seems to me the result quotes the work done by the field
 
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