physicslady123
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- Homework Statement
- Calculate the work done in moving a proton 0.75 m in the same direction as the electric field
with a strength of 23 N/C
- Relevant Equations
- W=-qEd
W=-qEd
=-(1.6*10^-19)(23)(0.75)
= -2.76*10^-18 J
However, the answer is 2.76*10^-18 J. Why is the word done positive and not negative? Since it's traveling in the same direction as the electric field, shouldn't it be negative work?
=-(1.6*10^-19)(23)(0.75)
= -2.76*10^-18 J
However, the answer is 2.76*10^-18 J. Why is the word done positive and not negative? Since it's traveling in the same direction as the electric field, shouldn't it be negative work?