Recent content by physicslover2012

In the problem, it was assumed that at 0C, the speed of sound is 340 m/s. I also found out that the speed of sound at 0C is 331, so I think it is a mistake on the teachers' part. If the tube is open at both ends, we have the antinodes at the ends of the tube. I watched an online lesson where...

The fundamental frequency I calculated is f=c/(2*l)= 340 Hz. I calculated the next harmonic, which was f1=2*c/(2*l)=680 Hz. Then, I wrote again the formula, using this time another speed: f1=c'/(2*l) From here, I deducted that c'=680 m/s, and I found this formula online: c'=c+0,6*t. From here I...

During our classes, we haven't discussed the situation of a tube closed at both ends. But, assuming the position of the nodes and antinodes, I think it's a case similar to the one where the tube is open at both ends, so I think that f = v/λ = nv/(2L). Using the numeric data, my frequency would...