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maybe upload the image?

Homework Statement [/B] Consider a spherical planet of uniform density ρ. The distance from the planet's center to its surface (i.e., the planet's radius) is Rp. An object is located a distance Rfrom the center of the planet, where R<Rp. (The object is located inside of the planet.) Find a...

Time is up, and I have to do move on to other things. Thank you for helping me. I will go over it again soon!

I got the first part! three minutes left I took the integral of -2.7*2.95*(1/3)y^3 from 0 to 2.95 and I got that wrong. I figured the first part gives me 0, so I didn't do anything with it

I thought that it was giving me F that I would plug into the W = F*D. I am supposed to give W in terms of joules

Okay then. But for part A, was the answer that I got in joules? Am I supposed to do another calculation to get joules?

I calculated the integral for the first part and got -51.12, and then multiplied that by the sqrt(2*(2.95^2)) and got -213.3. It is still wrong. I do not know what to do.

I thought since it was dy, I would not so anything to the x, but the change would happen to the y part, unless I was supposed to change it to (1/3) y^3? My calculus is really rusty

So it would be the integral of -2.7x^3 dx from 0 to 2.95 Then for part B, is the first integral -2.7*0*dx from 0-2.95? and then the second one...since it is dy, then I could do -2.7*x*2y*dy from 0 to 2.95?

OH so y=x. Then for my final integral, it is the integral of x^3 dx from 0 to 2.95? (I may have that completely wrong.)

I do not know what you mean by y being a known function of x. Was my first integral correct, and then if I plug in the value of that integral into the W=F*D equation, then it works?

Or would it be the integral of -2.7*y^2*dx from 0 to 2.95?

Please look at my math Could I write it as the integral from 0 to 2.95 of (-2.7*x*y^2) dx?

I do not know how to integrate the force along the path...Could you explain in detail?

Hello I am in the Eastern Time Zone by the way, so about 51 minutes left (!) For the first one, I took W=F*D and took F⃗ =−αxy^2 j-hat, plugged in α=2.70, x=2.95, y=2.95, and then multiplied that by the sqrt(2*2.95^2). I got -289. For the second one, I did the same thing but in two parts...