Recent content by physicsstudent111

The Vertical velocity is 7.5m/s

Vvertical=15sin30 = 7.5m/s d=Vvertical*t+0.5atsquared 0=(7.5m/s)t+0.5(-9.81m/s)t squared 0=t(7.5m/s-4.9t) t= 1.53s t=1.53/2 t= 0.76s to reach the maximum height Is this correct?

I think the melting point for water is 0 degrees. But I am not really sure what to say about the energy. Does there have to be more energy to fully melt the ice?

In the graph we can say the heater warms the water 10 degrees every 75s and to melt ice we need to reach a temperature of 0 degrees

Im not really sure how to answer this question. Would you have any ideas?

Thank you!

Because that's what the question states

Q=Qwarm water+Qsteam Q=mct+mLv Q=(8kg)(4200J)(100C-25C)+(2kg)(2.3*10 to the power of 6 J/Kg) Q=7.12*10 to the power of 6 J Is this the correct answer?

I assumed that Force of gravity is equal to Fn. So I did 1.8kg(9.80m/s(down))=17.64N. But I think this is wrong

About a week. Do you have any suggestions for this question?

I have no idea how to start this other than that I think that Fn is 17.64N and Fnet is 0. But I don't have the mew, so I am not sure how I am going to get the force of static friction.