Recent content by pilotguy
-
P
Point of equilibrium between charges
I'm not sure; the question is a little ambiguous on that. Does it make a difference to the solution from earlier in the thread?- pilotguy
- Post #14
- Forum: Introductory Physics Homework Help
-
P
What Factors Affect the Resistance and Drift Velocity of a Copper Wire?
Yeah, I noticed that. I tried it with the correct conversion (.356 m) and 5577 amps was what I found for current. Isn't that really high though?- pilotguy
- Post #6
- Forum: Introductory Physics Homework Help
-
P
What Factors Affect the Resistance and Drift Velocity of a Copper Wire?
Except that gives a current of 5577 amps for the second part. What am I missing?- pilotguy
- Post #4
- Forum: Introductory Physics Homework Help
-
P
What Factors Affect the Resistance and Drift Velocity of a Copper Wire?
Hmm. Density of Cu=8.96 g/cm^3 (8.96g/cm^3 * 1 / 10g)^-1=1.119 cm^3 Ohh, that gives you a volume! D'oh! V=1.119 cm^3 1.119=pi*r^2*L L=1.119/(pi*.1^2) L=35.605 cm So, R=rho(L/A) R=(1.899*10^-8)(.0356)/(3.142*10^-6) R=2.152*10^-4 ohms Does this sound right?- pilotguy
- Post #3
- Forum: Introductory Physics Homework Help
-
P
What Factors Affect the Resistance and Drift Velocity of a Copper Wire?
Homework Statement A 10-g piece of copper is to be formed into a wire of radius 1.0 mm at a temperature of 50° C. What is the resistance of this wire? (Hint: you will need to look up the density of copper.) If a potential of 12 V is put across this wire, what is the drift velocity...- pilotguy
- Thread
- Copper Copper wire Resistance Wire
- Replies: 6
- Forum: Introductory Physics Homework Help
-
P
Point of equilibrium between charges
Perfect! Thanks for the help!- pilotguy
- Post #12
- Forum: Introductory Physics Homework Help
-
P
Point of equilibrium between charges
I see. Any guess as to what was my professor trying to get at with his hint about the discriminant in the quadratic equation?- pilotguy
- Post #10
- Forum: Introductory Physics Homework Help
-
P
Point of equilibrium between charges
So there's no equilibrium between them; does that mean that there's only equilibrium at +/- infinity? That would reduce the force to essentially zero. I'm a little lost.- pilotguy
- Post #7
- Forum: Introductory Physics Homework Help
-
P
Point of equilibrium between charges
Oh, I think I see what you're saying. If the + charge is on the left, and the - charge is on the right, with a positive test charge between them, the test charge will be repelled from the positive charge and attracted toward the negative charge, meaning that both forces would act to the right...- pilotguy
- Post #5
- Forum: Introductory Physics Homework Help
-
P
Point of equilibrium between charges
So does that mean that it's Frep=ke*(q'*q+)/x^2 and Fattr=ke*(q'*q-)/(d-x)^2? Then equate them and solve for x?- pilotguy
- Post #3
- Forum: Introductory Physics Homework Help
-
P
Point of equilibrium between charges
Homework Statement Take two charges, one positive with charge q+, and another with charge q- are at a distance d away from each other. Under what conditions is there a point of equilibrium and, if it exists, where would it be located? Show mathematically. (Hint: use the quadratic equation...- pilotguy
- Thread
- Charges Equilibrium Point
- Replies: 16
- Forum: Introductory Physics Homework Help