Recent content by pinkpistachios

I got it, thanks :)

If I combine the masses so it's one system and then apply N2L: 3 = F / 620 so 1860 = Fsfr ?

3 = (- Fplow on ox + Fsfr )/500 1500 = (- Fplow on ox + Fsfr) 1500N would be the net horizontal force right? Would that be the magnitude of Fsfr ?

I have acceleration and mass, so would I use Newton's second law a = ∑F/m?

Homework Statement A 500 kg ox runs and speeds up by 3 m/s2, but is held back by a 120 kg plow that is attached to its back. Assuming the coefficient of static friction between the horse's hooves and the soil is 0.73, what is the magnitude of the static friction force the soil exerts on the...