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Expressing series in terms of a Power Series
Corrected, thank you- pkmpad
- Post #3
- Forum: Calculus and Beyond Homework Help
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Expressing series in terms of a Power Series
Hello and thank you for trying to help. In spite of the fact that this seems a very simple problem, I do not find myself able to get a solution. Here it goes: Let $$f(x)=\displaystyle \sum_{k=3}^\infty a_k \frac{x^k}{k(k-1)(k-2)}$$ and $$g(x)=\displaystyle \sum_{k=0}^\infty a_k x^k$$. Express...- pkmpad
- Thread
- Calculus Calculus 1 Power Power series Series Terms
- Replies: 3
- Forum: Calculus and Beyond Homework Help
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Undergrad Solve Challenging Integral with Proven Techniques | x>1 Integer Solution
Thank you! That helps a lot in my problem in spite of being focused on the complex domain of the function -
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Undergrad Solve Challenging Integral with Proven Techniques | x>1 Integer Solution
Breaking it in 4 fractions would definitively lead to a sum of divergent integrals, but dividing it into 2 integrals: x \displaystyle \int_2^\infty \frac{1}{y(y^2-1)\log(x+y)} + \int_2^\infty \frac{1}{(y^2-1)\log(x+y)} Since the value of the second one is too small for large x, any idea... -
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Undergrad Solve Challenging Integral with Proven Techniques | x>1 Integer Solution
Thank you for your interest. If I tried that, wouldn't I have a sum of divergent integrals? -
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Undergrad Solve Challenging Integral with Proven Techniques | x>1 Integer Solution
Hello. I am having a lot of trouble trying to solve/analyse this integral: $$\displaystyle \int_2^\infty \frac{x+y}{(y)(y^2-1)(\ln(x+y))} dy$$ I have tried everything with no result; it seems impossible for me to work with that natural logarithn. I have also tried to compute it, as it...