Recent content by PMANNAS

I'll need to read this through a few times to make sure I understand. I'm still unsure why it's obvious that the left rod will have greater tension than the one on the right (although I tried using Chasles theorem in the previous post). I cannot understand why there is a force from the support...

Maybe I could split the problem into a net eccentric force acting on each arm like the images below. Look at the 1st image further below: This could be the yellow net eccentric force applied on the left arm which, according to 'Chasles Theorem', causes a clockwise couple about the COM (ie. M...

I'm not sure how there can be an asymmetry but obviously it is happening. Is it because one arm (ie. the left one) is being bowed inwards (concave) while the other arm ( the right one) outwards?

Yes , I understand that there must be an imbalance in the forces F1 and F2 but I had problems visualising how that could physically happen. The pivot arms are rotating and there must be centripetal forces pulling in the rods (and would bend them if they weren't rigid). So the arms would tend...

Ahhh! Now I think I can visualise it . So the centripetal forces via the pivot arms will start pulling on lower arms increasing the strain tension which means there will be pull forces acting on mass M by both arms. When those forces are added together we will get a centripetal and tangential...

I'm more interested in how that centripetal force can physically be achieved . It must be via the 2 arms connecting to mass M . You've mentioned that I am missing forces done by the support , so are you able to draw some force diagrams (no need for maths) to just show me how that centripetal...

Yes , I can see that a 'Centripetal Force' can be theoretically worked out but I cannot see how it could be physically achieved.

Yes , that was what I assumed but it looks that I may be wrong according to other member's posts.

Look at the image below where I've drawn a rigid triangle, with thin lightweight rods and a fixed mass M attached as shown. There is a constant torque (2Fr) applied at a fixed pivot point P bisecting the top rod. Let's assume M is at rest and then a torque is added about pivot point P which will...

My understanding of certain topics in physics has been flawed so now trying to learn it all over again. The internet is a fantastic place to relearn misunderstood concepts.