Recent content by Polarbear10

Thanks! That's what I reckon too, so I set up the equation using P1 as 241,2kPa and P2 being 186kPa. Ended up getting a height (h2) of 3 meters (rounded)..

Hi! Did you mean that the velocity can or can't change since the flowmass must be constant? But would it be correct to say that P1; is the new pressure on the pressure gauge (3) = 241,2kPa? And P2 being what I calculated in task 3?

Hi, everyone! Doing some fluid flow/Bernoulli tasks. Ok, so the task is: «A hose with a radius of 0,035m is connected to a nozzle, which reduces the radius of the hose to 0,018m (2). The hose carries (qv) 0,0075 m3/sec and the totalpressure (3) in the wide section (1) is 211 kPA. The density of...

You're right, however on tests and on exams we are only allowed to use pen and papir and calculator. No computers.

Yes, I got 6.098 and rounded it up to 6,1kg. But the process is correct? What is the real difference between Q1 and Q4? With Q1 being: Heat of fusion water * mass of ice = 334400 * x = 334400J And Q4: Specific heat capacity for ice* m * ∆T=> 2097*x*12 = 25164J Because isn't both of these the...

Do I need to make a Q4, for the process when the ice goes from 0-12°C? Using Specific heat capacity for ice* m * ∆T=> 2097*12 = 25164J Then in the end, add together Q1+Q2+Q4 / Q3(The heat lost) Q1 334400 +Q2 229900 + Q4 25164 = 589464J Q3 = 3594800J 3594800J/589464J = 6,01 kg Am I getting...

I just can't seem to get the correct result.. what numbers did you get? I bet it would be easier using a computer yes, I just really want to learn how to do it on paper before using a computer. :smile: So ok, the ice goes from -12, freezing, and into melting at 0°C.. For Q1, I then used the...

Any tips on how I do it?o_O

I tried using heat capaity for water, ended up with the mass of ice being 5,8kg..

Hello! I'm having some problems solving a task.. "Ice with temperature -12°C is used to cool down water from 98°C. to 55°C. . Specific heat capacity for ice = 2097J/kgK, Secific heat capacity water: 4180 j/kgK. Heat of fusion for water is 334,4kJ7K. The mass of the water is 20kg." ∆T water =...