Recent content by Prague

Alright, thanks a lot I understand everything now. Now on to writing. Thank to everyone for the help.

Ah, I understand this now. Thank you, hopefully this will get me by on my paper. I'll use this to prove there is a time difference, then I can say that the paradox is which twin is aging slowly because each twins reference is that the other twin is slowing down. And the simple answer is, the...

Hmm, alright I see now. So let's see, \gamma \equiv \frac{1}{\sqrt{1-\frac{v^2}{c^2}}} gives me the seconds for the twin opposite the observer. Which is 7.08881205 t = \gamma t_0 (not sure what this one is used for. and L = \frac{L_0}{\gamma} gives me the days/year...

so what would those two final equations look like? Also, t_0 is the time experienced by A (homebound twin) and t is the time experienced by B (traveler) right? Thanks, I was confused at first with all the different ways I was told to solve it but I am getting it now.

Oh sorry, Twin A and B live on X blah blah blah when B departs their age set to 0. Twin B travels 3 light years at .99c and then returns at the same speed.

Ok so I take the twin that ticks just one second will be twin B (who traveled away) and the twin that ticks 7.08881205 is the one on Earth (twin a) Alright now how do i figure out how long twin A is away for in B's reference and how long twin B is away for in A's reference?

Hey, I seem to be confused now. I can't seem to mathematically solve my problem anymore with the correct way. Can anyone help me? Actually I did it, but I did it like this. \gamma \equiv \frac{1}{\sqrt{1-\frac{v^2}{c^2}}} where, \gamma \equiv...

Thanks alot, I'll take a look at that page and report back if I have any other questions.

Oh, alright. That makes more sense. So what makes this a paradox? What is the math behind it that shows it is a paradox and how did Einstein solve it to prove it wasn't a paradox? Or, to just relate to the situation I posted, how can you make this a paradox? I think you can make it a paradox...

The argument is that B will be younger than A. It's a bad assignment, all he said was make a 1,000 word argument about anything you want. All you need is 6 published references (which I found) and an arguement. I figured I'd have some fun with it and actually learn something in the process...

well, i did state that the planet A stays on is at constant inertia. So therefore, wouldn't B need to acc. anyways to get to the speed of light right off the planet?

Two twins, A and B are born on the planet X, which has a constant inertial rate. At the time of B's departure from X both A and B had an age of 0. Twin B travels 3 light years at a speed of 99c. Once reaching the destination of 3 light years, twin B returns to X again at 99c. What age will A and...

Two twins, A and B are born on the planet X, which has a constant inertial rate. At the time of B's departure from X both A and B had an age of 0. Twin B travels 3 light years at a speed of 99c. Once reaching the destination of 3 light years, twin B returns to X again at 99c. What age will A and...

Wait, so is the work you did above correct? Or is there a part missing? Also, why does it take him slightly less time to get to reach his destination if he is traveling at .99c? Isn't .99c 99% of c? Thus, he would be traveling at 184,140 miles per second opposed to 186,000 miles per second...