Recent content by PrecalcStuden

Can't thank you enough, but i'll be sure to help other members in return with what i can. Thanks again

danago, Thank you so much! yes that does make sense to me, because a positive times a positive equals a positive and a negative times a negative is a positive. I see why that would be a solutkion Is there anyway I can repay you for all your help?

I see I have to keep an eye on that, if I'm having the same confuzino here. BTW, thank you for your time, can't say that enough, I am stressing about a big math final. Like for example on antoher one I am stuck e ^( x^2 - 4x) > = e ^ 5 I take the natural log of both sides and it...

But I didn't write down the problem wrong. I really don't understand where I missed the sign change.

I don't understand, i wrote down the problem correctly, and i just change the original problem to better see it to: log (base e) (2-5x ) > 2 Then I change it to the exponential form e^2 > 2-5x Did I miss something with the change of signs?

You're correct sir, but I still can't get my greater than or less than sign to match up. I'm mulitplying top and bottom by -1 so that's twice making my < sign stay the same. Thanks for over looking my work my kind sir, but just missing one part of the puzzle : )

Thank you so much for over looking my work. Let's see, I've think I've simplied it correctly this time, but is there a way to get it really bone dried simplied? Thanks for your help I've got = e^2 > 2- 5x = e^2 - 2 > -5 x = ( e^2 - 2) / -5 < x I can't get the signs to match...

Homework Statement The problem is ln ( 2 - 5x) > 2 Homework Equations The answers for the back of the book is x < (2-e^2) / 5 The Attempt at a Solution Here's my attempt ln ( 2 - 5x ) > 2 = ln 2 - ln 5x > 2 = - ln 5x > 2 - ln 2 = x < (2- ln 2) / -ln 5 Is there...

Integral, thank you kind sir. Let's see here. Yes sir. Looks like it will be ln 80 + .033t = ln 59.8 + .001t From there ln 80 - ln 59.8 = .001t - .033t ln 80 - ln 59.8 = -.032 then divide and use a calculatrosomething isn't adding up quite right sir, I am getting a negattive numbe[/I]...

WOULD SOMEONE PLEASE HELP ME im begging yiou guys

would someone please help me I am freaking begging you. I am down on my knees

would someone pklease help me. I am begign you guys. I need help with this. geeze

integral, i beg of you. i just really need someone to help me with this mroe in depth. I've been waiting all day, i would really appreciate it integral. please

so will it then turn into ln 8.0 (.033t) = ln 59.8 (.001t) Please I've been wait all day just to solve this one dang problem.

I know that, but this is a weird one with weird coefficients. Please just walk me through this. gosh, I am stressing out already