Recent content by priya amrute

i will be really glad if u can help me with this...we am working on a project where the calculation of resonant frequency is very important for which we require...

i looked around a lot..all i know is Decreasing the separation of the plates, decreases the voltage of the capacitor since the electric-field is not affected by the distance between the plates. The voltage on the capacitor is V=Ed. Therefore the voltage increases. For a constant charge, Q, C=Q/V...

what if the distance between the plates is much larger than the diameter of the parallel plates?? how do we then calculate the capacitance?