Recent content by Pro @ RL

That is not the definition of the electric potential difference. If you look at what you wrote you see you are integrating across a surface, dS right? therefore it would have to be a double integral, so that equation itself is not even mathematically correct, please look up the correct equation...

The reason why it is dL and not dS is by definition of the equation you need to use, you may have selected the wrong one or an out of context one. Admittedly dL is taken over a closed loop, so it does enclose a surface, but in this configuration of the question where you are moving across the...

Since you are relating the potential to the potential difference you need to take one bound of the integral to be infinity(zero voltage reference) and the other to be the point d. The potential is a measure of the amount of energy it it takes to move from infinity to some point close to the...