Recent content by psykatic

Well, the acceleration is basically the pull of the earth, called acceleration due to gravity. It has a fixed value of 9.8 or approximately 10!

okay, that's fine with me, I've several more problems over the free body diagrams! I'll post it in mean time! Thank You!

Well, did you have a look at the diagram? It hasnt been approved yet..

Well, I spent 2 full size papers working on it! And I had so many doubts rushing one after the another, and that was because of just one wrong interpretation, gawd! Mark44, I did take the slop to be, \frac{-1}{27cot\theta}, members should start using LaTex codes now, understanding the...

Homework Statement A smooth ring A of mass m can slide on a fixed horizontal rod. A string tied to the ring passes over a fixed pulley B and carries a block C of Mass M (=2m) as shown in the given figure. At a instant at the string between the ring and the pulley makes an angle \theta with...

Yes, that's what Anna, I could not get to 10^{3/2}, which is why i asked you check the question! As of finding the intercepts, all looks good to me!

Thank You, now back to MarquisDM..

Well, please check the question once! I'm facing a petty problem..

Well, (3,1,1) are the direction ratios! And if this line passes through (4,5,5), substitue it in the general equation, \frac{x-x_1}{a}=\frac{y-y_1}{b}=\frac{z-z_1}{c} where, (a,b,c) are the direction ratios and (x_1,y_1,z_1) is the point through which the line passes!

Pal, I've helped you a lot with this, you need to have your own input over it, give it a try!

As to my methodology, \lim_{x\rightarrow\infty}\frac{xsinx}{x^2+1} Taking x^2 common, we have the above equation as, \lim_{x\rightarrow\infty}\frac{x^2(\frac{sinx}{x})}{x^2(1+\frac{1}{x^2})} Now, cancelling x^2 terms and also we know that \frac{1}{\infty}=~0, Thus, the function tends to...

Rather, the solution to (b) would be, sin\theta=~\frac{-1}{27cot\theta}.27cos\theta +~b Therefore, sin\theta=~\frac{-sin\theta}{27cos\theta}.27cos\theta +~b Thus, 27cos\theta gets canceled and the value of b turns out to be 2sin\theta Therefore, the equation would be, 27ycos\theta...

Well, pal.. i don't find a reason to make this thing so complicated, when it isnt! :). Go a bit systematically, you have been given the equation of the ellipse which is, \frac{x^2}{27^2} +\frac{y^2}{1^2}=~1 Now substitue, the value of x in the above given equation, thus, you have...

oh, yes! got it! actually i was considering one train, and observing it going past the others!

Well, from the given question it is evident that the equation which to be found is of a line. Now, the equation, \frac{x-11}{3}=\frac{y+8}{1}=\frac{z-4}{1} directly gives you the direction ratios of the required line, isn't it? What would they be?