Recent content by Purple94

i ask my lecturer and she said this question is wrong

I get this: x-y+3kz=0 (-k+2)y +(1-6k)z=0 (2-3k^2)z=0 let z=u, (2-3k^2)u=0 2u-3k^2=0 -3k^2u=-2u k^2u=2/3u k^2=2/3 k=2/3,-2/3

I try, i get the value of k is not equal to zero

the other 2 equation is (-k+2)y + (1-6k)z=0, (2-3k^2)z=0

But, according to my attempt to this solution, i get this equation is has no solution. How can to prove this equation is infinetely solution?

Homework Statement 1. Determine the values of k such that the following homogeneous linear system has infinitely number of solutions. My problem is: I cannot to find the value of k Homework Equations 2x – ky + z = 0 -x + y – 3kz = 0 kx – 2y + 2z = 0 The Attempt at a Solution After I...