Recent content by Quicksilvr

Ok, thanks for your help.

https://en.wikipedia.org/wiki/Gauss%27s_law states the following: By the divergence theorem, Gauss's law can alternatively be written in the differential form: where ∇ · E is the divergence of the electric field, ε0 is the electric constant, and ρ is the total electric charge density (charge...

And what about the fact that the law states that the divergence is non-zero everywhere?

But the divergence is not defined as a delta function. Can you show me why you think it is a delta function using the wikipedia definition? Additionally as I said before, Gauss' law states that the divergence is non-zero everywhere.

I'm trying to figure out the mathematical details right now. I'm trying to avoid usage of delta functions because there was no rigorous definition for them in my textbook (and the distribution definition in wikipedia seems complicated). In any case, while true that the divergence does not vanish...

1) I am treating the divergence as a function at each point (is there any other way to define it? the wikipedia definition states that the definition of the divergence as an integral around the point is equivalent to this definition when the function is continuously differentiable), defined as...

I'm trying to understand how the integral form is derived from the differential form of Gauss' law. I have several issues: 1) The law states that ## \nabla\cdot E=\frac{1}{\epsilon 0}\rho##, but when I calculate it directly I get that ## \nabla\cdot E=0## (at least for ## r\neq0##). 2) Now ##...