Recent content by Quix270

I think it could be because the weight on the left side are very close to the center, that means less down force, and the weight on the right side is very far from the center. So I think it's possible to have 3 weight on one side. The final distance are 25, 35, 45 and 95cm. Can you explain me...

I think I got it. Is 35cm Using net torque equation (0.25)(9.8)+(0.05)(9.8)+(x)(9.8)-(0.45)(9.8)=0 The answer of that is 15cm from the center but the problem give me distance from left to right so 50-15=35cm

Ok I understand in this point

I make it again with other perspective. Does the answer is 15cm?

There is where I have trouble. The problem say one weight is at 95cm but not say from what and It couldn't be from the center because the rod is 1m long. Cold be at 45cm if I substract 95 from the center that is 50. That would be right?

It's the graphic correct?

Please help me I don't have idea. I'm frustrated right now. Can you give the answer an say me how you get there?

Si the answer is at 50cm? At the center of the rod? Can you explain me with numbers how you get there? I will appreciate that. I have test tomorrow

I make it by assuming the distance are taking from the left side of the rod because it's impossible to have a mass 95cm separated from the center of the rod since the rod length is 1 m.

I make that and give me 25cm. So the other mass have to be above another mass. Can you tell me where I get wrong? Thanks again

I assume is like the draw below. Can you explain me how you get to the answer please? I think too they give the measurements from left to right of the rod

Here are. Thank you!

I think is 25cm but I'm not sure. Help please

What would happen if a coil is exposed to North Pole of magnet who are in movement?

What would happen if a coil it’s exposed to a moving magnetic field with only north poles? Coils being exposed to only North Pole. Will produce alternate current or nothing?