Recent content by qwertyuiopasd
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Q
Proving Limit of [x^2 - 2x] / [x^3 - 5] as x->Infinity = 0
Spidey you are wrong. e[x][/SUP]/x goes to infinity. The denominator goes to infinity also but the limit is not 0!- qwertyuiopasd
- Post #8
- Forum: Calculus and Beyond Homework Help