Hello TalonD and all,
According to the
P=10(1/37)(1/37)(1/37)(36/37)(36/37)
posted above, the probability of a specific number appearing at least one time in 37 spins would be:
P= 37 (1/37) (37/37) (37/37)...(37/37) = 37(1/37)(37/37)^36=37(1/37)=1
which of course is incorrect.
What...