Recent content by racecar_

So the electric field will stay the same? For the equation energy density = (1/2)εE^2, what changes then? Yeah, I think it's a better approach. In what situations should I use finding the stored energy and dividing the volume rather than (1/2)εE^2, and vice versa? Thanks.

I am confused about how the electric field changes in this problem - is E' = E/Ke=E/2? Is E = V/d a correct usage? When I solve it this way, the answer is incorrect: change in energy density = (1/2)ε(E'2- E2) = (1/2)ε(E2/4 - E2) = (1/2)ε(-3/4)(V/2d)2. What am I doing wrong? Thanks.