Recent content by Raihn

A typical protein contains 16.2% nitrogen (14.00674 mg/mmol). A 0.500 mL aliquote of protein solution was digested, and the liberated NH3 was distilled into 10.00mL of 0.02140 M HCL. The unreacted HCl required 3.26mL of 0.0198 M NaOH for complete titration. Find the concentration of protein (mg...

Or is Q negative, where T1 = 278.15 and T2 = 288.15?

It's probably not clicking in my head since I'm studying for organic chemistry II and doing this at the same time, but this is what I did: c = [0.20 + 1.4(288.15) + 0.023(288.152))] - [0.20 + 0.14(278.15) + 0.023(278.152)] c = 494.78 Then: Q=(2.0g)(494.718(288.15-278.15) Q = 9894.36

I did it again and I got Q = 9894.36. I don't think that's right. This question is so simple I don't know why I'm not getting it.

Oh ok, I see thanks a lot. Didn't notice I skipped that part. Thanks again.

Why divide by 2? And I thought I did take the integral? I couldn't figure out how to add the 15 and 5 onto the integral sign, but I thought I did solve it in that manner? Maybe not? Now I've confused myself lol.

Homework Statement The specific heat of a substance varies with temperature according to: c = 0.20 + 0.14T + 0.023T^{2}, with T in deg-C and c in cal/gK. Find the energy required to raise the temperature of 2.0g of this substance from 5.0C to 15C. Homework Equations Q=mc\DeltaT K= C +...