Recent content by ratinatinycar

I am not sure I understand the question, but I have since figured out the solution. The missing piece of information that I did not know was that charge must be conserved before and after the distance is doubled because of the closed circuit. Q0 = QF Q0 = C1V1 + C2V2 (C2V2)VB = (2.0 x...

Unfortunately, no. I am extremely insecure of what my thought process should be. I have done this problem before so some information regarding it I still remember, but I am afraid of knowing how to do this problem from memorization. I would really like to understand not only what I need to do...

Hello, and thank you! I understand that doubling the distance of the plates halves the capacitance, so the capacitance goes from 10.0 μF to 5.00 μF in one of the capacitors.

Homework Statement Two identical parallel-plate capacitors, each with capacitance 10.0 μF, are charged to potential difference 50.0 V and then disconnected from the battery. They are then connected to each other in parallel with plates of like sign connected. Finally, the plate separation in...