Recent content by RavageU

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    Parallel Capacitors connected to Battery then D/C

    So because they are parallel, the voltage across the plate have to be the same, so I have: V' = q1/c1 = q2/c2 and solving simulatenous, I get: q1 + (c2/c1)q1 = Q1 - Q2 Plug in the numbers, and I get ~3507 which is still the wrong answer...
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    Parallel Capacitors connected to Battery then D/C

    So would it be Q1-Q2 (The initial charges of the capacitor) = q1 + q2 (The charges after reconnection)?
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    Parallel Capacitors connected to Battery then D/C

    Edited for more that I've done to solve the problem. So the charges essentially cancel out?
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    Parallel Capacitors connected to Battery then D/C

    Homework Statement Capacitors of 19.1 uF and 2.1 uF are charged as a parallel combination across a 229 V battery. The capacitors are disconnected from the battery and from each other. They are then connected positive plate to negative plate and negative plate to positive plate. Find the...