Recent content by Rawr

There are two different problems that I am confused with: 1) The taste of mature cheese is related to the concentration of lactic acid in cheese. Use the concentrations of lactic acid in 30 samples of cheddar cheese on page 15. Well, what's important is that using all the numbers it gave...

I was studying my brother's old notes to prepare me for my upcoming AP Biology class. I read over six main functional groups (hydroxyl, carbonyl, carboxyl, amino, sulfhydrl, phosphate) and subsequently, there were follow-up questions. One of them asked to draw a molecule with all of the six...

A 1.5-cm tall object is placed 0.50 m to the left of a diverging lens with a focal length of 0.20 m. A converging lens with a focal length of 0.17 m is located 0.08 m to the right of the diverging lens. What is the height and orientation with respect to the original object of the final image...

No, I am not going to ask you what the difference between those two are. =P I know the differences, but at the beginning of this term, my class started to learn about electricity and magnets, and that stuff. Now, vector quantities are those that have direction and scalars are those without...

The derivative of the difference between people leaving and entering.. gives you the rate of people leaving and entering? That does not make much sense to me.. seeing as it's the difference between the two.

Ah, thank you very much for that tip. That worked out much better. Now, I have a different question. It says that... H(t) = [PLAIN]http://upload.wikimedia.org/math/a/6/8/a68014a267c9e7ec058affc9f338d7f2.png(from[/URL] 9 to t) (E(x) - L(x)) dx for 9 < t < 23. The value of H(17) to the nearest...

Homework Statement The rate at which people enter an amusement park on a given day is modeled by the function E defined by: E(t) = 15600/(t² - 24t + 160). The rate at which people leave the same amusement park on the same day is modeled by the function L defined by: L(t) = 9890/(t² - 38t...

Which force is responsible for holding a car in a frictionless banked curve? The answer is the horizontal component of the normal force. But could anyone explain why that is? I thought it would be the horizontal component of the weight since normal force is vertical?

Why would it go to b^2? o_o; It's supposed to be g(b), and g(x) is -x^2 + 2x -5. lol, probably from my careless typing <.< *EDIT* So, I have 2b^2 - 4b + 6 / (1-2b) = 2-2b 2b^2 - 4b + 6 = (2-2b)(1-2b) 2b^2 - 4b + 6 = 2 - 6b + 4b^2 2b^2 - 2b -4 = 0 Factor that out to get (b - 2) (2b + 2) b...

Aw man, I just realized I did my math wrong. For the slope equation, it's supposed to be 2b^2 - 4b + 6 / (1-2b) How would I solve for b if I'm not given that it equals anything?

Oh! Wow, that answer now, seems so blantant ~_~ So, a = 1-b Substitute that into the slope equation: (1-b) ^2 - (-b^2 + 2b -5) 1 - 2b + b^2 + b^2 - 2b + 5 = 2b^2 - 4b + 6 Oookay. Then I need to solve for the equation to get b. The thing is I get two answers so how do I know which one is...

Oh, sorry. The graph is supposed to have one tangent line that hits both f(x) and g(x).

Ah.. thank you, I get it now. It doesn't matter if you use the alternate form or not, heh. The next part says use the coordinates of A and B to write an expression for the slope AB in terms of a and b. So... f(a) - f(b)/ (a - b) I think that's what I'm supposed to do. The next part...

I'm given f(x) = x^2 and g(x) = -x^2 + 2x - 5 And it says Let A (a, f(a)) be the point of tangency on f(x) and B (b, g(b)) be the point of tangency on g(x). Use calculus to find the slope of the tangent line at each point. What must be true about these two slope expressions? I know we...

Problem: Find the resultant of the three displacement vecotrs in the drawing by means of the component method. The magnitudes of the vectors are A = 5.00 m, B = 5.00 m, and C = 4.00 m. http://img179.imageshack.us/img179/6690/picturels2.jpg <-- there's the picture. I found the...