Recent content by razored

Almost everyone I know has this tendency---sometimes myself. Maybe it is because people are used to believing and accepting supernatural claims? These gullible people. More generally used in religion : "my grandma was on her death bed set to die in a week from cancer, but then was cured...

I understand what you mean by TRUE acceleration. I guess the author was intending to find instantaneous velocities,which can be pretty accurately approximated, over a time interval.Thank you for the advice/help.

This is a graph which shows time and displacement as function of time. I am told to find the average acceleration for the first ten and sixteen seconds. The answers are : 2.5 and 0.7 cm / s 2 . If the image is not showing below, download the attached image...

Never mind, I figured it out. Thanks anyway!

Homework Statement Prove the law of sines using a vector cross product. (Hint, consider the area of the triangle and that A+B+C=0.) Homework Equations |A||C|sin ( θ ) = (a2c3 − a3c2) + (a3c1 − a1c3) + (a1c2 − a2c1) The Attempt at a Solution The farthest I went is to show .5...

Yeah, I should have multiplied out the RHS. I will leave it at that. I guess the author did intend it as a practice of multiplying polys. Thanks.

Any alternatives beside this?

But that is not what I am supposed to do; I am supposed to work it out and arrive at that result that they set equal to. My(and yours) efforts are supposed to = (x-y)(x^{n-1}+x^{n-2}y+ \cdots + xy^{n-2}+y^{n-1}) .

I am trying to get to that result. I think multiplying the RHS and cancelling with the terms on the LHS just tests if they are equal.

That defeats the entire purpose of the problem, if I understand you correctly.

"In particular, you appear to be forgetting that the ellipsis encompasses a lot of terms (everything from xn-3y2 to x2yn-3). " Yeah I forgot to include them. "You are on the right way, just you need to factor the negative terms (with minus before them), and the positive terms (with plus before...

Homework Statement Prove x^n-y^n= (x-y)(x^{n-1}+x^{n-2}y+ \cdots + xy^{n-2}+y^{n-1}). The Attempt at a Solution x^n-y^n = \\ =x^n -y^n + x^{n-1}y - x^{n-1}y + x^{n-2}y^2 - x^{n-2}y^2 + y^{n-1}x - y^{n-1}x + y^{n-2}x^2 - y^{n-2}x^2 Adding inverses = x^n - x^{n-1}y -y^n +...

The last one should be with <=. I understand why it is there; I was just pissed because I would have never thought to put the <= after putting up absolute values around 2ab. Thanks for the help. HallsOfIvy, I do like your interpretation of the math better, more lucid. The GIF I posted is...

That's not true, plugin a=-3 and b=2. In fact, try any set of numbers and you will see.

http://math.ucsd.edu/~wgarner/math4c/derivations/other/triangleinequal_files/eq0007S.gif Why did they introduce the <= sign? I cannot think of any numbers that would violote the =. So why introduce the <?