Recent content by rdemyan

At this point my only question was about converting from the circular cross section to an elliptical cross section. I'm analyzing the impingement zone of equal impinging jets. The plane of symmetry of the impingement zone, I am assuming is effectively identical to the elliptical cross section...

The CFD diagram is rotated 90 degrees from the diagram that I showed. What I showed is a horizontal plate and if the CFD diagram had a plate it would be vertical. The outgoing stream is actually a sheet that has approximately an elliptical shape. Here's a snapshot of an animation of two equal...

Well, "M" is in a cross section of the jet before it impinges so it can't be a stagnation point and is instead referred to as a separation point. However, your point is well taken because I do want to project that ellipse downwards and have that be the elliptical plane of symmetry of the...

So, if I understand you correctly, what you have shown with your diagram and equations is that the mass flowrate through the elliptical cross section is the same as the mass flowrate through the circular cross section normal to flow. I "tentatively" stated that in my problem statement, but you...

The velocity profile for the jet, with respect to the circular cross sectional area normal to flow, is flat (i.e. no variation with radius within the jet; same velocity everywhere in the direction of flow). In Figure b, the flow is going into the hatched slit so it is flowing in the y...

I'm trying to solve a problem of a liquid jet impinging at an oblique angle, ##\beta##. This post only involves a portion of that problem. I'm thinking that I should look at the flow within the jet based on an elliptical cross section of the jet that is coplaner with the x-z axis (see attached...

For equal impinging streams where ##m_1 = m_2 = m;u_1=u_2=u## the kinetic energy equation is $$EL = \frac{2mu^2}{2} - \frac{2mv^2}{2} = mu^2 - mv^2$$ where EL means kinetic energy lost. Now when no energy is lost, ##v = u##. However, as I mentioned previously I have been stating that the...

Well, I'm still not really following. It sounds like your blobs are effectively spheres which can change mass. It would be interesting if you tried running some numbers, but I just don't see how you are going to have enough equations.

Yes, it reduces v but it also means that the v in the exiting streams is highly likely to be uniform for both exiting streams. If you don't assume the same v it seems unlikely to me that your method would be able to calculate ##m_b, m_f, \alpha, \phi##, which are the parameters of interest...

And what about the real case where energy is in fact given up in the impingement zone as a result of the collision. The energy dissipation results in some level of turbulence. The turbulent eddies homogenize any gradients and therefore it is likely that liquid ejected from that zone in...

If you maintain that the velocities of the exiting streams are different, then your proposed method is a dead end. I already provided convincing evidence that the velocities are the same.

Quoted from Wikepedia on coefficient of restitution: "For an object bouncing off a stationary target, e is defined as the ratio of the object's rebound speed after the impact to that prior to impact:$$e = \frac{v}{u}$$ where u is the speed of the object before impact v is the speed of the...

It occurs to me that knowing the maximum velocity possible from the collision of these two unequal streams might be useful. How would I mathematically determine the theoretical maximum velocity of the two streams after impingement. I'm not sure if this means that absolutely no energy would be...

"That's not what coefficient of restitution means. The COR is a property of the two bodies involved and tells you what the result would be for a head-on collision. Oblique collisions need to be handled as I indicated, separating the motions normal to and parallel to the plane of contact." The...

In my example in the previous reply, inelastic collisions lose a fair amount of energy and that is clearly shown. So, I don't understand why you are saying it is unrealistic. It turns out that if the velocity of the incoming streams is lower than the Taylor-Culick velocity (the velocity which...