Recent content by redrogue

Theodore Kaczynski (aka the Unabomber) . A Harvard graduate, former math professor at Berkeley, and a murderer - he was as unstable as they come, passing judgement on who should live or die (i.e. the socially elite) On a minor note he was a plagiarist.

The National Solar Observatory is also a good site to peruse as well. Cheers.

Isaac Asimov once said: Violence is the last refuge of the incompetent. Cheers.

INTJ here as well. Cheers.

This is correct by Kirchoff's junction rule. Yes, this is correct. The potential difference in a circuit loop is equal to zero. However a more correct way to present your answer would be: 8V-I_1(2\Omega)=0 8V=I_1(2\Omega) I_1=4A -8V-I_2(8\Omega)+16V=0 8V=I_2(8\Omega) I_2=1A...

My goal (and hope) is to study the sun, particularly its internal oscillations.

Overpaid: Venture Capitalists. It's absolutely rediculous what these vultures make. I should know since I worked for a failed startup in Silicon Valley funded by these...did I say vultures? Underpaid: Teachers, Nurses Cheers.

Anything in the Myst series, currently URU. Move over Everquest and Neverwinter Nights. Cheers.

Interesting topic. It coincides with my avatar. :smile: If I could I'd like to have the powers of (or even be for a day) Ororo Munroe better known as Storm of the X-men...the wind witch. Cheers.

My favorite types: New age, space music, ambient electronica and ethnic rhythms fused with modern dance with some classic rock thrown in: Enya Enigma Deep Forest Delerium Afro Celt Sound System October Project Fleetwood Mac Stevie Nicks I also listen to following Internet stations...

950N is the normal force the person experiences. The person's weight must be subtracted out to get the net force which is 950N-818N=132N. Using Newton's 2nd Law, we can can find the acceleration. F=ma implies a=\frac{F}{m} where F =132N and m is the mass of the person found.

Actually you can solve for the mass of the person when he is at rest. At rest, acceleration is due to gravity so: F_{1}=mg and m=\frac{F_{1}}{g} where g=9.81\frac{m}{s^2} and F_{1}=818N.

It looks like it may have one, but if it truly represents the 'Net, there should be no center. Network operators strive for redundancy so that most every major network node has multiple access points, particularly on the backbones.

Yep! and you got to love Megatokyo! ...but the caffeine molecule tee is my favorite...I've got two.

http://www.thinkgeek.com sells posters of these maps. They currently have http://www.thinkgeek.com/cubegoodies/posters/techie/29c2/, http://www.thinkgeek.com/cubegoodies/posters/techie/3433/, http://www.thinkgeek.com/cubegoodies/posters/techie/573c/ , and...