Greetings Flatland:
For any continuous function, f(x), on the interval [a,b], the average value of f on that interval is given by:
f_ave = 1/(b-a) * Integral f(x) dx ; [a,b]. So, in the present case,
f_ave = 1/(2+2) * Integral (4 - x^2) dx; [-2,2]
= (1/4)(4x - (1/3) x^3) =...