Recent content by Rizke

So I am writing a paper on superconductors, and i am trying to explain the meissner effect. However i seem to be running into conflicting information. I hoping some one can help clarify. The effect happens, when a magnet creates a change in flux, causing a induced current in the...

Okay i think i finally understand why we add to the pressure. Assuming the welder in this problem is at a location where there is one ATM pressure, the gauge does not account for this. So we need to add that 1 ATM, or 101325 PA to the final pressure reading. i get .374 kg

P = (3.0e^5)+100000 = 4.0e^5 (4.0e^5)(7.5e^-2) / (8.3144621)(309.65) = 11.6524 moles => 11.65*32 = 372.89 grams => .373 kg Awesome Thank you! p.s can i always add 100000 Pa for absolute pressure? that is if i already convert ATM to PA.

oh that's right a gauge will read zero, but there is actually the ATM pressure that is on the gauge. which is like 15 right? so i have to subtract that pressure after i convert it to pascals. or is this not right? Thanks for the quick reply.

A welder using a tank of volume 7.50×10^−2 m^3 fills it with oxygen (with a molar mass of 32.0 g/mol ) at a gauge pressure of 3.00×10^5 Pa and temperature of 36.5 ∘C. The tank has a small leak, and in time some of the oxygen leaks out. On a day when the temperature is 21.0 ∘C, the gauge pressure...