Recent content by Rizlablack

thank you very much D H.. I had some clues that could be something like that but now I'm quite sure I'm not doing anything wrong!

Hello everybody! I'm quite new with Matlab and I'm starting trying some stuff.. well I was trying to input det(a) where a=[1,2,3;4,5,6;7,8,9] and this should be zero. And I mean 0.0000 but the result is 6.6613e-16 why?O.o

THANK YOU!it's so easy now I just forgot to rename variable! and btw I made a mistake in the first post, it should be ..+ (1/2w) exp(2iwt) a*(-k) so there are no identities at all! ^_^ thanks again!

thank you for your help!but still I don't know how to match that formula with my integral!it's multiplied by phi(x) and integrating by part I don't manage to simplify things! what about just another little help? ^_^

hey guys!I really need help in getting from the real classical solution of the Klein Gordon equation to the expression of operators! I start from: \varphi(x) = \int \frac{d^3 k}{(2\pi)^3 2\omega} [a(\textbf{k}) e^{ikx} + a^{*}(\textbf{k}) e^{-ikx}] and should arrive with \int d^3 x \...

ok thanks a lot you all! ^_^

thanks guys you really clarify me that formula!And now I understand how to move through it! the only thing not clear is: given K^{\mu}_{\ \ \rho} = \partial_{\rho}\phi \partial^{\mu}\phi if I have to compute S^{\mu}=\frac{\partial}{\partial(\partial_{\mu} \phi )}K^{\mu}_{\ \ \rho}...

ok, I hope this is the right place to post this, that's my first post here! ^_^ Well I'm deriving the Noether's Current in terms of an improved energy momentum tensor and by now all the knowledge about tensors algebra and so on came from my own sadly. I'm stuck with a matter that probably...